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प्रश्न
Simplify using law of exponents.
(xm)0
योग
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उत्तर
(xm)0 = xm×0
= x0
= 1 ...[since (am)n = am×n, a0 = 1]
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अध्याय 3: Algebra - Exercise 3.1 [पृष्ठ ५२]
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संबंधित प्रश्न
Say true or false and justify your answer:
23 > 52
Simplify:
`(6^5)^4`
Write the following numbers using positive indices.
`(1/6)^-3`
Solve for x: `(2^(2x - 1))/(2^(x + 2))` = 4
Solve for x: `(5^5 xx 5^(-4) xx 5^x)/(5^12)` = 5−5
Which of the following is not equal to 1?
`[(7/11)^3]^4 = (7/11)^-`
`(6/13)^10 ÷ [(6/13)^5]^2 = (6/13)^-`
(–3)4 = –12
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
