Question

Write the first five terms of the following sequence whose nth term is:

a_n = 2n² – 3n + 1

Answer 1

a_n = 2n² – 3n + 1 

Put n = 1

A₁ = 2(1)² – 3(1) + 1 = 2 – 3 + 1 = 0

Put n = 2

A₂ = 2(2)² – 3(2) + 1 = 8 – 6 + 1 = 3 

Put n = 3

A₃ = 2(3)² – 3(3) + 1 = 18 – 9 + 1 = 10

Put n = 4

A₄ = 2(4)² – 3(4) + 1 = 32 – 12 + 1 = 21

Put n = 5

A₅ = 2(5)² – 3(5) + 1 = 50 – 15 + 1 = 36