Advertisements
Advertisements
प्रश्न
Write the expression for the moment of force about a given axis of rotation.
Advertisements
उत्तर
Moment of force (O) = F × Perpendicular distance of force from point O.
i.e. Moment of force = F × OP
APPEARS IN
संबंधित प्रश्न
In a door, handle is provided ......... from the hinges.
State one way to decrease the moment of a given force about a given axis of rotation.
A potter turns his wheel by applying a force through the stick near the rim of wheel.
State one factor on which the magnitude of a non-contact force depends. How does it depend on the factor stated by you?.
Name of S.I. unit of momentum.
A nut is opened by a wrench of length 10 cm. if the least force required is 5.0 N. find the moment of force needed to turn the nut.
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the difference of anticlockwise and clockwise moment
State one factor on which the magnitude of a non-contact force depends. How does the magnitude of a non-contact force change along with distance?
State the effects that a force can produce. Given one example of each.
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is ______.
