Advertisements
Advertisements
प्रश्न
Without actually calculating the cubes, find the value of the following:
(28)3 + (–15)3 + (–13)3
Advertisements
उत्तर
(28)3 + (–15)3 + (–13)3
Let x = 28, y = −15 and z = −13
It can be observed that,
x + y + z = 28 + (−15) + (−13)
= 28 − 28
= 0
It is known that if x + y + z = 0, then
x3 + y3 + z3 = 3xyz
∴ (28)3 + (–15)3 + (–13)3
= 3(28)(–15)(–13)
= 16380
APPEARS IN
संबंधित प्रश्न
Factorise the following:
8a3 + b3 + 12a2b + 6ab2
What are the possible expressions for the dimensions of the cuboids whose volume is given below?
| Volume : 3x2 – 12x |
Write in the expanded form:
(2a - 3b - c)2
If a + b + c = 0 and a2 + b2 + c2 = 16, find the value of ab + bc + ca.
Evaluate of the following:
463+343
Simplify of the following:
(x+3)3 + (x−3)3
Find the following product:
\[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{x}{y} - \frac{y}{3} \right) \frac{x^2}{16} + \frac{xy}{12} + \frac{y^2}{9}\]
If \[a^2 + \frac{1}{a^2} = 102\] , find the value of \[a - \frac{1}{a}\].
If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] =
If a − b = −8 and ab = −12, then a3 − b3 =
Use identities to evaluate : (101)2
The number x is 2 more than the number y. If the sum of the squares of x and y is 34, then find the product of x and y.
Use the direct method to evaluate :
(xy+4) (xy−4)
Simplify by using formula :
`("a" + 2/"a" - 1) ("a" - 2/"a" - 1)`
If p + q = 8 and p - q = 4, find:
pq
If `"p" + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`
If `"r" - (1)/"r" = 4`; find : `"r"^4 + (1)/"r"^4`
Without actually calculating the cubes, find the value of:
(0.2)3 – (0.3)3 + (0.1)3
