Advertisements
Advertisements
प्रश्न
The product (x2−1) (x4 + x2 + 1) is equal to
विकल्प
x8 − 1
x8 + 1
x6 − 1
x6 + 1
Advertisements
उत्तर
We have to find the product of `(x^2 - 1)(x^4 +x^2 +1)`
Using identity `(a^3 -b ^3) = (a-b)(a^2 +ab + b^2)`
Here `a=x^2 , b = 1`
`(x^2)^3 - (1)^3 = (x^2 - 1)[(x^2)^2 + x^2 xx 1 +1^2]`
`x^6 - 1 = (x^2-1)(x^4 + x^2 + 1)`
Hence the product value of `(x^2 - 1)(x^4 +x^2 +1)` is `x^6 - 1`.
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
`[1/4a-1/2b+1]^2`
Write the following cube in expanded form:
`[x-2/3y]^3`
Factorise the following:
`27p^3-1/216-9/2p^2+1/4p`
Give possible expression for the length and breadth of the following rectangle, in which their area is given:
| Area : 35y2 + 13y – 12 |
Evaluate the following using identities:
(2x + y) (2x − y)
Simplify the following products:
`(m + n/7)^3 (m - n/7)`
Simplify (2x + p - c)2 - (2x - p + c)2
Simplify of the following:
(2x − 5y)3 − (2x + 5y)3
Find the following product:
\[\left( 3 + \frac{5}{x} \right) \left( 9 - \frac{15}{x} + \frac{25}{x^2} \right)\]
Find the following product:
If a + b + c = 9 and a2+ b2 + c2 =35, find the value of a3 + b3 + c3 −3abc
If \[x^3 - \frac{1}{x^3} = 14\],then \[x - \frac{1}{x} =\]
If a + b = 7 and ab = 10; find a - b.
Evaluate: (6 − 5xy) (6 + 5xy)
Simplify:
`(x - 1/x)(x^2 + 1 + 1/x^2)`
Simplify:
(3a - 7b + 3)(3a - 7b + 5)
Factorise the following:
25x2 + 16y2 + 4z2 – 40xy + 16yz – 20xz
Give possible expressions for the length and breadth of the rectangle whose area is given by 4a2 + 4a – 3.
