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Why EΘ values for Mn, Ni and Zn are more negative than expected? - Chemistry

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प्रश्न

Why EΘ values for Mn, Ni and Zn are more negative than expected?

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उत्तर

Negative E° values of Mn2+ and Zn2+ are because of stabilities of half-filled (3d10 : Mn2+) and fully-filled (3d10 : Zn2+) configuration respectively.Mn2+ ion has higher EΘ value because of highest negative enthalpy of hydrogen.

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अध्याय 8: The d-and f-Block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १११]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 8 The d-and f-Block Elements
Multiple Choice Questions (Type - I) | Q 33 | पृष्ठ १११

संबंधित प्रश्न

The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co

Answer the following: Which element shows only +3 oxidation state?


In the series Sc (Z = 21) to Zn (Z = 30), the enthalpy of atomization of zinc is the lowest, i.e., 126 kJ mol−1. Why?


The `E_((M^(2+)//M))^Θ` value for copper is positive (+0.34 V). What is possibly the reason for this? (Hint: consider its high ΔaHΘ and low ΔhydHΘ)


Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?


Explain why Cu+ ion is not stable in aqueous solutions?


How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.


Compare the stability of +2 oxidation state for the elements of the first transition series.


What is meant by ‘disproportionation’? 


Which metal in the first series of transition metals exhibits +1 oxidation state most frequently and why?


Give reasons: Sc3+ is colourless in aqueous solution whereas Ti3+ is coloured.


The transition metals show _________ character because of the presence of unpaired· electrons and Cu+ is ____________ because of its electronic configuration is [Ar]3d10


Electronic configuration of Mn2+ is ____________.


Generally transition elements form coloured salts due to the presence of unpaired electrons. Which of the following compounds will be coloured in solid-state?


Transition elements form binary compounds with halogens. Which of the following elements will form \[\ce{MF3}\] type compounds?

(i) \[\ce{Cr}\]

(ii) \[\ce{Co}\]

(iii) \[\ce{Cu}\]

(iv) \[\ce{Ni}\]


Match the catalysts given in Column I with the processes given in Column II.

Column I (Catalyst) Column II (Process)
(i) \[\ce{Ni}\] in the presence of hydrogen (a) Zieglar Natta catalyst
(ii) \[\ce{Cu2C12}\] (b) Contact process
(iii) \[\ce{V2O5}\] (c) Vegetable oil to ghee
(iv) Finely divided iron (d) Sandmeyer reaction
(v) \[\ce{TiCl4 + Al (CH3)3}\] (e) Haber's Process
  (f) Decomposition of KCIO3

Assertion: The highest oxidation state of osmium is +8.

Reason: Osmium is a 5d-block element.


The basic character of transition metals monoxide follow the order.


The second ionization enthalpies of chromium and manganese are 1592 and 1509 kJ/mol respectively. Explain the lower value of Mn.


Explain the use of different transition metals as catalysts.


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