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Why +2 oxidation state of manganese is more stable? - Chemistry

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प्रश्न

Why +2 oxidation state of manganese is more stable?

लघु उत्तरीय
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उत्तर

  1. Manganese, having five unpaired electrons, exhibits six different oxidation states. The small energy difference between the 3d and 4s orbitals allows manganese to lose electrons from both, resulting in oxidation states ranging from +2 to +7.
  2. Electronic configuration of Mn2+ = [Ar]3d54s0
  3. Half-filled (d5) d-orbitals provide the Mn2+ ion additional stability, making Mn in the +2 oxidation state more stable.
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2012-2013 (March)

संबंधित प्रश्न

 
 
 

Complete the following chemical equations:

`(i) Cr_2O_7^(2-)+6Fe^(2+)+14H^+ ->`

`(ii) 2CrO_4^(2-)+2H^+ ->`

`(iii) 2MnO_4^-+5C_2O_4^(2-)+16H^+ ->`

 
 
 

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(Atomic nos. : Mn = 25, Cr = 24)


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Column I
(Aqueous solution of salt)
Column II
(Colour)
(i) \[\ce{FeSO2.7H2O}\] (a) Green
(ii) \[\ce{NiCl2.4H2O}\] (b) Light pink
(iii) \[\ce{MnCl2.4H2O}\] (c) Blue
(iv) \[\ce{CoC12,6H2O}\] (d) Pale green
(v) \[\ce{Cu2 Cl2}\] (e) Pink
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Answer the following question:

Which element of the first transition series has highest third ionisation enthalpy?


On the basis of the figure given below, answer the following questions:

  1. Why Manganese has lower melting point than Chromium?
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\[\ce{3MnO^{2-}4 + 4H^+ -> \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{} + 2H2O}\]


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\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\], E0 = +0.77 V

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(Atomic number of Cr = 24)


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Cr2+/Cr −0.9 V
Mn2+/Mn −1.2 V
Fe2+/Fe −0.4 V
Cr3/Cr2+ −0.4 V
Mn3+/Mn2+ +1.5 V
Fe3+/Fe2+ +0.8 V

Use this data to comment upon:

The ease with which iron can be oxidised as compared to a similar process for either chromium or manganese metal.


The E° value for the Mn2+/Mn2+ couple is more positive than that of Cr3+/Cr2+ or Fe3+/Fe2+ due to the change of:


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