Advertisements
Advertisements
प्रश्न
Which would undergo SN2 reaction faster in the following pair and why ?
Advertisements
उत्तर
Primary alkyl halides prefer to undergo SN2 reactions than tertiary alkyl halides because of less steric hindrance experienced by the approaching nucleophile. Hence, out of the given pair (CH3−CH2−Br) would undergo SN2 reaction faster.
APPEARS IN
संबंधित प्रश्न
Write the major products(s) in the following:
Write the structures of A, B and C in the following:
Which of the following is the correct order of decreasing SN2 reactivity?
Identify the end product (C) in the following sequence:
\[\ce{C2H5OH ->[SOCl2][Pyridine] A ->[KCN {(alc.)}] B ->[2H2O/H^+] C}\]
The increasing order of nucleophilicity would be:
A primary alkyl halide would prefer to undergo ______.
Which of the following statements are correct about the kinetics of this reaction?
(i) The rate of reaction depends on the concentration of only (b).
(ii) The rate of reaction depends on concentration of both (a) and (b).
(iii) Molecularity of reaction is one.
(iv) Molecularity of reaction is two.
The number of chiral alcohol (s) with molecular formula C4H10O is ______.
Assertion (A) : Nucleophilic substitution of iodoethane is easier than chloroethane.
Reason (R) : Bond enthalpy of C-I bond is less than that of C-Cl bond.
Which one of the following chlorohydrocarbons readily undergoes solvolysis?
