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प्रश्न
Which of the following are the roots of 3x2 + 2x – 1 = 0?
`1/3`
योग
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उत्तर
The given equation is (3x2 + 2x – 1 = 0)
On subtracting `x = 1/3` in the given equation, we get :
L.H.S = 3x2 + 2x – 1
= `3 xx (1/3)^2 + 2 xx 1/3 - 1`
= `3 xx 1/9 + 2/3 - 1`
= `(1 + 2 - 3)/3`
= `0/3`
= 0
= R.H.S
Thus, `(1/3)` is a root of (3x2 + 2x – 1 = 0)
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अध्याय 4: Quadratic Equations - EXERCISE 4A [पृष्ठ १८२]
