Question

Which of the following are the roots of 3x² + 2x – 1 = 0? 

`-1/2`

Answer 1

The given equation is (3x² + 2x – 1 = 0)

On subtracting `x = (-1/2)` in the given equation, we get 

L.H.S = 3x² + 2x – 1 

= `3 xx (-1/2)^2 + 2 xx (-1/2) - 1` 

= `3 xx 1/4 - 1 - 1` 

= `3/4 - 2` 

= `(3 - 8)/4` 

= `(-5)/4 ≠ 0`

Thus, L.H.S = R.H.S. 

Hence, `(-1/2)` is a solution of (3x² + 2x – 1 = 0)