Question

Which expression gives stopping potential \[V_0\] in terms of frequency?

विकल्प

• \[V_0=\frac{h}{e}\nu-\frac{e}{\phi_0}\]

• \[V_0=\frac{h}{e}\nu-\frac{\phi_0}{e}\]

• \[V_0=\frac{h}{e}\nu+\frac{\phi_0}{e}\]

• \[V_0=\frac{e}{h}\nu-\frac{\phi_0}{e}\]

Answer 1

Dividing \[eV_0=h\nu-\phi_0\] by \[e\] gives \[V_0=\frac{h}{e}\nu-\frac{\phi_0}{e}\]. This expresses stopping potential in terms of frequency and the work function.