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प्रश्न
Which expression gives stopping potential \[V_0\] in terms of frequency?
पर्याय
\[V_0=\frac{h}{e}\nu-\frac{e}{\phi_0}\]
\[V_0=\frac{h}{e}\nu-\frac{\phi_0}{e}\]
\[V_0=\frac{h}{e}\nu+\frac{\phi_0}{e}\]
\[V_0=\frac{e}{h}\nu-\frac{\phi_0}{e}\]
MCQ
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उत्तर
Dividing \[eV_0=h\nu-\phi_0\] by \[e\] gives \[V_0=\frac{h}{e}\nu-\frac{\phi_0}{e}\]. This expresses stopping potential in terms of frequency and the work function.
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