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प्रश्न
When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is ______
विकल्प
6 J
12 J
15 J
20 J
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उत्तर
When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is 12 J.
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संबंधित प्रश्न
Deduce the expressions for the kinetic energy and potential energy of a particle executing S.H.M. Hence obtain the expression for the total energy of a particle performing S.H.M and show that the total energy is conserved. State the factors on which total energy depends.
Deduce the expression for kinetic energy, potential energy, and total energy of a particle performing S.H.M. State the factors on which total energy depends.
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`(cos45^circ=1/sqrt2)`
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