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प्रश्न
What happens when methanal undergoes cannizzaro reaction?
Give the chemical equation:
What happens when formaldehyde undergoes Cannizzaro’s reaction?
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उत्तर १
When methanal (formaldehyde, HCHO) undergoes the Cannizzaro reaction, it results in the formation of formic acid HCOOH and methanol CH3OH.
The Cannizzaro reaction is a base-catalyzed disproportionation reaction that occurs with non-alpha-hydrogenated aldehydes (like methanal). In this reaction, one molecule of formaldehyde gets reduced to methanol CH3OH, while the other gets oxidized to formic acid HCOOH.
The reaction can be represented as
\[\ce{2HCHO ->[NaOH] HCOOH + CH3OH}\]
उत्तर २
Methanal will undergo Cannizzaro reaction as it possesses α-hydrogen to form methanol.
\[\begin{array}{cc}
\phantom{.}\ce{H}\phantom{..............................}\ce{H}\phantom{.......}\ce{H}\phantom{...........}\phantom{..}\\
\backslash\phantom{..............................}|\phantom{.........}\backslash\phantom{..........}\\
\ce{2C = O + conc{.}KOH -> H - C - OH + C - O- K+}\\
/\phantom{..............................}|\phantom{.........}/\phantom{..........}\\
\ce{\underset{Methanal}{H}}\phantom{.........................}\ce{\underset{Methanol}{H}}\phantom{.}\ce{\underset{methanoate}{\underset{Potassium}{H}}}\phantom{............}\\
\end{array}\]
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संबंधित प्रश्न
Write a note on the self oxidation-reduction reaction of an aldehyde with a suitable example.
Write the chemical equation for the reaction involved in Cannizzaro reaction.
An organic compound with the molecular formula C9H10O forms 2, 4-DNP derivative, reduces Tollens’ reagent and undergoes Cannizzaro reaction. On vigorous oxidation, it gives 1, 2-benzenedicarboxylic acid. Identify the compound.
Describe the following:
Cannizzaro reaction
Write the equation involved in the following reaction:
Etard reaction
Complete the following reactions:

Write the product formed when p-nitro chlorobenzene is heated with aqueous NaOH at 443K followed by acidification?
Complete the following reaction:

Explain the following reaction:
Cannizzaro reaction
\[\begin{array}{cc}
\ce{D}\phantom{........................}\\
|\phantom{.........................}\\
\ce{2D - C = O + OH^- ->[Cannizzaro] X and Y}
\end{array}\]
(Y is alcohol, D is deuterium)
X and Y will have the structure:
