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प्रश्न
What are the absolute extrema of \[f(x)=12x^{\frac{4}{3}}-6x^{\frac{1}{3}}\] on \[-1,1\]?
विकल्प
Absolute maximum value \[\frac{-9}{4}\] at \[x=\frac{1}{8}\], and absolute minimum value \[18\] at \[x=-1\].
Absolute maximum value \[0\] at \[x=0\], and absolute minimum value \[6\] at \[x=1\].
Absolute maximum value \[18\] at \[x=-1\], and absolute minimum value \[\frac{-9}{4}\] at \[x=\frac{1}{8}\].
Absolute maximum value \[6\] at \[x=1\], and absolute minimum value \[0\] at \[x=0\].
MCQ
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उत्तर
The values at the endpoints and critical points are \[18,0,-9/4,6\]. Comparing these values shows that \[18\] is greatest and \[-9/4\] is least.
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