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Verify Rolle'S Theorem for the Following Function on the Indicated Interval F(X) = X2 − 4x + 3 on [1, 3] ? - Mathematics

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प्रश्न

Verify Rolle's theorem for the following function on the indicated interval f(x) = x2 − 4x + 3 on [1, 3] ?

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उत्तर

\[f\left( x \right) = x^2 - 4x + 3\]

We know that a polynomial function is everywhere derivable and hence continuous.
So, being a polynomial function, 

\[f\left( x \right)\]is continuous and derivable on \[\left[ 1, 3 \right]\] .

Also,

\[f\left( 1 \right) = \left( 1 \right)^2 - 4\left( 1 \right) + 3 = 1 - 4 + 3 = 0\]

\[f\left( 3 \right) = \left( 3 \right)^2 - 4\left( 3 \right) + 3 = 9 - 12 + 3 = 0\]

\[ \therefore f\left( 1 \right) = f\left( 3 \right) = 0\]

Thus, all the conditions of Rolle's theorem are satisfied.
Now, we have to show that there exists \[c \in \left( 1, 3 \right)\] such that \[f'\left( c \right) = 0\] .

We have

\[f\left( x \right) = x^2 - 4x + 3\]

\[ \Rightarrow f'\left( x \right) = 2x - 4\]

\[ \therefore f'\left( x \right) = 0 \Rightarrow 2x - 4 = 0 \Rightarrow x = 2\]

Thus, 

\[c = 2 \in \left( 1, 3 \right) \text { such that } f'\left( c \right) = 0\]

Hence, Rolle's theorem is verified.

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अध्याय 15: Mean Value Theorems - Exercise 15.1 [पृष्ठ ९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 15 Mean Value Theorems
Exercise 15.1 | Q 2.2 | पृष्ठ ९

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