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Using ruler and compass only, construct a ΔABC such that BC = 5 cm and AB = 6.5 cm and ∠ABC = 120° (i) Construct a circumcircle of ΔABC. (ii) Construct a cyclic quadrilateral ABCD - Mathematics

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प्रश्न

Using ruler and compass only, construct a ΔABC such that BC = 5 cm and AB = 6.5 cm and ∠ABC = 120°

  1. Construct a circumcircle of ΔABC
  2. Construct a cyclic quadrilateral ABCD, such that D is equidistant from AB and BC.
ज्यामितीय चित्र
योग
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उत्तर

  1. Construct a circumcircle of ΔABC.
    • Construct ΔABC using BC = 5 cm, AB = 6.5 cm, and ∠ABC = 120°.
    • Draw the perpendicular bisectors of AB and BC.
    • Their point of intersection O is the circumcentre.
    • With centre O and radius OA (or OB or OC), draw a circle.
      This circle is the circumcircle of ΔABC.
  2. Construct a cyclic quadrilateral ABCD such that D is equidistant from AB and BC.
    • Draw the angle bisector of ∠ABC.
    • Extend it to meet the circumcircle at point D.
    • Since D lies on the angle bisector, it is equidistant from AB and BC.
    • Join AD and DC to obtain a cyclic quadrilateral ABCD.

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अध्याय 16: Constructions - CHAPTER TEST [पृष्ठ ३७०]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 16 Constructions
CHAPTER TEST | Q 3. | पृष्ठ ३७०
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