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प्रश्न
Using prime factorisation, find the HCF and LCM of 30, 72, 432.
योग
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उत्तर
30 = 2 × 3 × 5
72 = 2 × 2 × 2 × 3 × 3 = 23 × 32
432 = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 24 × 33
HCF = product of smallest power of each common prime factor in the numbers
= 2 × 3
= 6
LCM = product of greatest power of each prime factor involved in the numbers
= 24 × 33 × 5
= 2160
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