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प्रश्न
Using prime factorisation, find the HCF and LCM of 24, 36, 40.
योग
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उत्तर
24 = 2 × 2 × 2 × 3 = 23 × 3
36 = 2 × 2 × 3 × 3 = 22 × 32
40 = 2 × 2 × 2 × 5 = 23 × 5
HCF = product of smallest power of each common prime factor in the numbers
= 22
= 4
LCM = product of greatest power of each prime factor involved in the numbers
= 23 × 32 × 5
= 360
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अध्याय 1: Real Numbers - EXERCISE 1B [पृष्ठ १७]
