Advertisements
Advertisements
प्रश्न
Use the direct method to evaluate the following products :
(3x – 2y) (2x + y)
Advertisements
उत्तर
(3x – 2y) (2x + y) = (3x × 2x) + (3x × y) + (−2y × 2x) + (−2y × y)
= 6x2 + 3xy − 4xy − 2y2
= 6x2 − xy − 2y2
APPEARS IN
संबंधित प्रश्न
If `x + 1/x = sqrt5`, find the value of `x^2 + 1/x^2` and `x^4 + 1/x^4`
If the volume of a cuboid is 3x2 − 27, then its possible dimensions are
If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]
Use identities to evaluate : (998)2
Evalute : `( 7/8x + 4/5y)^2`
If a2 - 5a - 1 = 0 and a ≠ 0 ; find:
- `a - 1/a`
- `a + 1/a`
- `a^2 - 1/a^2`
Use the direct method to evaluate the following products:
(x + 8)(x + 3)
If p + q = 8 and p - q = 4, find:
pq
If `"a" + (1)/"a" = 2`, then show that `"a"^2 + (1)/"a"^2 = "a"^3 + (1)/"a"^3 = "a"^4 + (1)/"a"^4`
Find the value of x3 – 8y3 – 36xy – 216, when x = 2y + 6
