Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c.
Advertisements
उत्तर
We know that,
`(a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)`
`=> (a + b + c)^2 = 16 + 2(10)` [`∵ a^2 + b^2 + c^2 = 16` and ab + bc + ca = 10]
`=> (a + b + c)^2 = 16 + 20`
`=> (a + b + c) = sqrt36`
`=> a + b + c = +-6`
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(x + 8) (x – 10)
Expand the following, using suitable identity:
(x + 2y + 4z)2
Expand the following, using suitable identity:
(–2x + 5y – 3z)2
Evaluate the following using suitable identity:
(998)3
Evaluate following using identities:
(a - 0.1) (a + 0.1)
Simplify the following:
0.76 x 0.76 - 2 x 0.76 x 0.24 x 0.24 + 0.24
Simplify the following products:
`(1/2a - 3b)(1/2a + 3b)(1/4a^2 + 9b^2)`
Evaluate of the following:
1113 − 893
Find the following product:
If a + b = 6 and ab = 20, find the value of a3 − b3
(a − b)3 + (b − c)3 + (c − a)3 =
The product (x2−1) (x4 + x2 + 1) is equal to
Use identities to evaluate : (502)2
If a + `1/a`= 6 and a ≠ 0 find :
(i) `a - 1/a (ii) a^2 - 1/a^2`
Use the direct method to evaluate :
(xy+4) (xy−4)
Evaluate the following without multiplying:
(999)2
If `"a" - 1/"a" = 10`; find `"a"^2 - 1/"a"^2`
Simplify:
(4x + 5y)2 + (4x - 5y)2
Using suitable identity, evaluate the following:
101 × 102
