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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 7

Two Taps Can Fill a Cistern in 10 Hours and 8 Hours Respectively. a Third Tap Can Empty It in 15 Hours. How Long Will It Take to Fill the Empty Cistern, If All of Them Are Opened Together ? - Mathematics

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प्रश्न

Two taps can fill a cistern in 10 hours and 8 hours respectively. A third tap can empty it in 15 hours. How long will it take to fill the empty cistern, if all of them are opened together?

योग
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उत्तर

First tap can fill a cistern in 10 hours

Second tap can fill the cistern in 8 hours

Third tap can empty the cistern in 15 hours

∴ First tap's 1 hour's work = `1/10`

Second tap's 1 hour's work = `1/8`

and third tap's 1 hour's work = `1/15`

If all of them are opened together, then

heir one hour's work = `1/10 + 1/8 - 1/15`

`= (12 + 15 - 8)/120 = (27 - 8)/120 = 19/120`

∴ They can fill the cistren in =`120/19` hours

`= 6 6/19` hours

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अध्याय 7: Unitary Method (Including Time and Work) - Exercise 7 (C)

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सेलिना Concise Mathematics [English] Class 7 ICSE
अध्याय 7 Unitary Method (Including Time and Work)
Exercise 7 (C) | Q 6
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