Advertisements
Advertisements
प्रश्न
Two ropes, one 8 meters long and the other 12 meters long are to be cut into pieces of the same length. What will the maximum possible length of each piece be?
Advertisements
उत्तर
Length of one rope = 8 m
Length of other rope = 12 m
The maximum possible length of each piece of rope of the same length that can be cut from the two given ropes is the HCF of 8 m and 12 m.
Factors of 8: 1, 2, 4, 8
Factors of 12: 1, 2, 3, 4, 6, 12
Common factors of 8 and 12: 1, 2, 4
HCF of 8 and 12 = 4
∴ Maximum possible length of each piece of rope of same length = 4 m
Thus, the maximum possible length of each piece of rope is 4 m.
संबंधित प्रश्न
Find the HCF of the numbers in each of the following, using the prime factorization method:
144, 252, 630
Find the HCF of the numbers in each of the following, using the division method:
391, 425, 527
Find the HCF of the numbers in each of the following, using the division method:
1794, 2346, 4761
The HCF of 144 and 198 is
Find the largest number which divides 630 and 940 leaving remainders 6 and 4 respectively.
Two tankers contain 850 litres and 680 litres of kerosene oil respectively. Find the maximum capacity of a container which can measure the kerosene oil of both the tankers when used an exact number of times.
Find the HCF set of numbers using prime factorisation method.
51, 85
What is the HCF of two consecutive numbers?
Find the HCF of the following numbers:
30, 42
The length, breadth, and height of a room are 825 cm, 675 cm, and 450 cm respectively. Find the longest tape which can measure the three dimensions of the room exactly.
