Advertisements
Advertisements
प्रश्न
Two ropes, one 8 meters long and the other 12 meters long are to be cut into pieces of the same length. What will the maximum possible length of each piece be?
Advertisements
उत्तर
Length of one rope = 8 m
Length of other rope = 12 m
The maximum possible length of each piece of rope of the same length that can be cut from the two given ropes is the HCF of 8 m and 12 m.
Factors of 8: 1, 2, 4, 8
Factors of 12: 1, 2, 3, 4, 6, 12
Common factors of 8 and 12: 1, 2, 4
HCF of 8 and 12 = 4
∴ Maximum possible length of each piece of rope of same length = 4 m
Thus, the maximum possible length of each piece of rope is 4 m.
संबंधित प्रश्न
Find the HCF by the division method and reduce to the simplest form.
`275/525`
Simplify:
`322/391`
Find the HCF of the numbers in each of the following, using the prime factorization method:
84, 98
Two tankers contain 850 litres and 680 litres of kerosene oil respectively. Find the maximum capacity of a container which can measure the kerosene oil of both the tankers when used an exact number of times.
Find the G.C.D of the following:
3a2, 5b3, 7c4
G.C.D of any two prime numbers is __________
The G.C.D of x4 – y4 and x2 – y2 is
Find the HCF set of numbers using prime factorisation method.
18, 24
Find the HCF set of numbers using prime factorisation method.
61, 76
Find the HCF set of numbers using prime factorisation method.
84, 120
