हिंदी

Two forces F1 = F2 are applied on a wheel of radius 1.5 m, such that moment of couple is 30 Nm. Calculate the magnitude of each of the force.

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प्रश्न

Two forces F1 = F2 are applied on a wheel of radius 1.5 m, such that moment of couple is 30 Nm. Calculate the magnitude of each of the force.

संख्यात्मक
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उत्तर

Given: Moment of couple = 30 Nm, Radius = 1.5 m

∴ Arm of couple = 2 × radius = 2 × 1.5 m = 3 m

Moment of couple = Force × arm of couple

\[ \text{Force} = \frac{\text{Moment of couple}}{\text{Arm of couple}} \]

\[=\frac{30\ \text{Nm}}{3\ \text{m}}\]

= 10 N

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अध्याय 1: Forces: Turning Forces and Uniform Circular Motion - NUMERICAL PROBLEMS ON MOMENT OF FORCE [पृष्ठ १६]

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 10
अध्याय 1 Forces: Turning Forces and Uniform Circular Motion
NUMERICAL PROBLEMS ON MOMENT OF FORCE | Q 3. | पृष्ठ १६
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