Advertisements
Advertisements
प्रश्न
Thrice a number decreased by 5 exceeds twice the number by 1. Find the number.
Advertisements
उत्तर
Let the number be x.
Then, thrice of this number = 3x and twice of this number = 2x.
If we decrease thrice of x by 5, we get (3x – 5)
According to the question,
(3x – 5) – (2x) = 1
⇒ 3x – 5 – 2x = 1
⇒ x – 5 = 1
⇒ x = 1 + 5 ...[Transposing (–5) to RHS]
⇒ x = 6
Hence, the required number is 6.
APPEARS IN
संबंधित प्रश्न
In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180°).
The sum of three times a number and 11 is 32. Find the number.
In a test Abha gets twice the marks as that of Palak. Two times Abha's marks and three times Palak's marks make 280.
The solution of the equation is ______.
In a bag there are 5 and 2 rupee coins. If they are equal in number and their worth is ₹ 70, then
There are ______ 5 rupee coins and ______ 2 rupee coins.
In a Mathematics quiz, 30 prizes consisting of 1st and 2nd prizes only are to be given. 1st and 2nd prizes are worth ₹ 2000 and ₹ 1000, respectively. If the total prize money is ₹ 52,000 then show that:
The solution of the equation is ______.
If 5 is added to three times a number, it becomes the same as 7 is subtracted from four times the same number. This fact can be represented as ______.
A number is 7 more than one-third of itself.
The sum of twice a number and 4 is 18.
A number when divided by 6 gives the quotient 6. What is the number?
In a certain examination, a total of 3768 students secured first division in the years 2006 and 2007. The number of first division in 2007 exceeded those in 2006 by 34. How many students got first division in 2006?
