Advertisements
Advertisements
प्रश्न
Three 250 W heaters are connected in parallel to a 100 V supply, Calculate the energy supply in kWh to the three heaters in 5 hour.
Advertisements
उत्तर

The energy supplied to heaters:
Total power consumption = 250 + 250 + 250 = 750 W.
∴ Energy supplied in kWh in 5 hours
`= ("Watt" xx "hour")/1000`
`= (750 xx 5)/1000` kWh
= 3.75 kWh.
संबंधित प्रश्न
Name the commercial unit of electric energy.
An electric bulb is rated at 220 V, 100 W. (a) what is its resistance? (b) what safe current can be passed through it?
An immersion heater rated 1000 W, 220 V is used to heat 0.01 m3 of water. Assuming that the power is supplied at 220 V and 60% of the power supplied is used to heat the water, how long will it take to increase the temperature of the water from 15°C to 40°C?
Define electric power. An electrical device of resistance R is connected across a source of voltage V and draws a current I. Derive an expression for power in terms of current and resistance.
With reference to the diagram shown below calculate:

(i) The equivalent resistance between P and Q.
(ii) The reading of ammeter.
(iii) The electrical power between P and Q.
How can electric energy consumed by an electric appliance be calculated in kilowatt hour (kWh)?
An electric lamp A of 40 W and another electric lamp B of 100 W are connected to 220 V supply. Calculate the ratio of their filament resistances?
An electric iron is rated at 230 V, 750 W. What is its resistance? What maximum current can be passed through it?
1 kWh = ______ J.
