Advertisements
Advertisements
प्रश्न
The velocity of light in diamond is 121000 kms-1. What is its refractive index?
Advertisements
उत्तर
Speed of light in diamond = 121,000 km/s
= 121 × 106 m/s
Refractive index of diamond = `"Speed of light in air"/"speed of light in diamond"`
= `(3xx10^8)/(121xx10^6"m/s")`
= 2.48
संबंधित प्रश्न
Light of a single colour is passed through a liquid having a piece of glass suspended in it. On changing the temperature of liquid, at a particular temperature the glass piece is not seen. When is the glass piece not seen?
When a lighted candle is held in front of a thick plane glass mirror, several images can be seen, but the second image is the brightest, give reason.
Fig 4.31 below shows a light ray of single colour incident normally on two prisms A and B. In each case draw the path of the ray of light as it enters and emerges out of the prism. Mark the angle wherever necessary.
A ray of light strikes the surface at a rectangular glass slab such that the angle of incidence is 45o.
In each case, draw diagram to show the path taken by the ray as it passes through the glass slab and emerges from it.
The critical angle for glass-air interface is :
Name the material for which the refractive index is found to be maximum.
State the relation between the refractive index μ and the velocity of light (vm) in that medium.
Explain with the help of a diagram of how fish is able to see the objects above it.
Draw a diagram of a prism and label:
(i) the base,
(ii) the refracting surfaces,
(iii) the refracting edge,
(iv) the refracting angle in it.
The diagram below shows two parallel rays A (Orange) & B (Blue) incident from air, on air-glass boundary.
- Copy and complete the path of the rays A and B.
- How do the speeds of these rays differ in glass?
- Are the two refracted rays in glass parallel? Give a reason.
