Question

  The value of C_p − C_v is 1.00 R for a gas sample in state A and 1.08 R in state B. Let p_Aand p_B denote the pressures and T_A and T_B denote the temperatures of the states A and B, respectively. It is most likely that

विकल्प

•  p_A < p_B and T_A > T_B

•  p_A > p_B and T_A < T_B

• p_A = p_B and T_A < T_B

• p_A > p_B and T_A = T_B

Answer 1

 p_A < p_B and T_A > T_B

C_p − C_v  = R for the gas in state A, which means it is acting as an ideal gas in that state, whereas C_p − C_v = 1.08R in state B, i.e. the behaviour of the gas is that of a real gas in that state. To be an ideal gas, a real gas at STP should be at a very high temperature and low pressure. Therefore, P_A < P_B and T_A > T_B where P_A and P_B denotes the pressure and T_Aand T_B denotes the temperature of system A and B reepectively.