हिंदी

The total cost function for production of x articles is given as C = 100 + 600x – 3x2 . Find the values of x for which total cost is decreasing. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

The total cost function for production of x articles is given as C = 100 + 600x – 3x2 . Find the values of x for which total cost is decreasing.

योग
Advertisements

उत्तर

Given, the cost function is

C = 100 + 600x - 3x2

∴ `"dC"/"dx" = 0 + 600 - 6"x"`

= 600 - 6x

= 6(100 - x)

Since total cost C is a decreasing function,

`"dC"/"dx" < 0`

∴ 6(100 - x) < 0

∴ 100 - x < 0

∴ 100 < x

∴ x > 100

∴ The total cost is decreasing for x > 100.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Applications of Derivatives - Exercise 4.4 [पृष्ठ ११२]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 4 Applications of Derivatives
Exercise 4.4 | Q 3 | पृष्ठ ११२

संबंधित प्रश्न

Find the marginal revenue if the average revenue is 45 and elasticity of demand is 5.


A manufacturing company produces x items at the total cost of Rs (180 + 4x). The demand function of this product is P = (240 − x). Find x for which profit is increasing.


Find the elasticity of demand, if the marginal revenue is 50 and price is Rs 75.


The demand function of a commodity at price P is given as, D = `40 - "5P"/8`. Check whether it is increasing or decreasing function.


The total cost of manufacturing x articles C = 47x + 300x2 – x4 . Find x, for which average cost is decreasing


Find the price, if the marginal revenue is 28 and elasticity of demand is 3.


If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 5 comment on the result.


If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 2 comment on the result


For the demand function D = 100 – `p^2/2`. Find the elasticity of demand at p = 10 and comment on the results.


For the demand function D = 100 – `"p"^2/2`. Find the elasticity of demand at p = 6 and comment on the results.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which revenue is increasing.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which also find an elasticity of demand for price 80.


Fill in the blank:

A road of 108 m length is bent to form a rectangle. If the area of the rectangle is maximum, then its dimensions are _______.


If the elasticity of demand η = 1, then demand is ______.


If 0 < η < 1, then the demand is ______.


If the average revenue is 45 and elasticity of demand is 5, then marginal revenue is ______.


The manufacturing company produces x items at the total cost of ₹ 180 + 4x. The demand function for this product is P = (240 − 𝑥). Find x for which profit is increasing


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price per item is given as p = 120 – x. Find the value of x for which profit is increasing

Solution: Total cost C = 40 + 2x and Price p = 120 − x

Profit π = R – C

∴ π = `square`

Differentiating w.r.t. x,

`("d"pi)/("d"x)` = `square`

Since Profit is increasing,

`("d"pi)/("d"x)` > 0

∴ Profit is increasing for `square`


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price per item is given as p = 120 – x. Find the value of x for which elasticity of demand for price ₹ 80.

Solution: Total cost C = 40 + 2x and Price p = 120 – x

p = 120 – x

∴ x = 120 – p

Differentiating w.r.t. p,

`("d"x)/("dp")` = `square`

∴ Elasticity of demand is given by η = `- "P"/x*("d"x)/("dp")`

∴ η = `square`

When p = 80, then elasticity of demand η = `square`


Complete the following activity to find MPC, MPS, APC and APS, if the expenditure Ec of a person with income I is given as:

Ec = (0.0003)I2 + (0.075)I2

when I = 1000


If f(x) = x3 – 3x2 + 3x – 100, x ∈ R then f"(x) is ______.


If 0 < η < 1 then the demand is ______.


In a factory, for production of Q articles, standing charges are ₹500, labour charges are ₹700 and processing charges are 50Q. The price of an article is 1700 - 3Q. Complete the following activity to find the values of Q for which the profit is increasing.

Solution: Let C be the cost of production of Q articles.

Then C = standing charges + labour charges + processing charges

∴ C = `square` 

Revenue R = P·Q = (1700 - 3Q)Q = 1700Q- 3Q2

Profit `pi = R - C = square`

 Differentiating w.r.t. Q, we get

`(dpi)/(dQ) = square`

If profit is increasing , then `(dpi)/(dQ) >0`

∴ `Q < square` 

Hence, profit is increasing for `Q < square` 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×