हिंदी

If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 2 comment on the result - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 2 comment on the result

योग
Advertisements

उत्तर

Given, demand function is D = 50 – 3p – p2 

∴ `"dD"/"dp" = 0 - 3 - 2"p"`

= `- 3 - 2"p"`

Elasticity of demand is given by

`eta =- ("p")/"D" * "dD"/"dp"`

∴ `eta = (-"p")/(50 - 3"p" - "p"^2) * (- 3 - 2"p")`

∴ `eta = (p(3 + 2p))/(50 - 3p - p^2)`

(i) When p = 5

`eta = (5(3 + 2xx 5))/(50 - 3(5) - (5)^2) = (5xx13)/(50 - 15 - 25)`

= `65/10 = 6.5`

Since η > 1 the demand is elastic

(ii) When p = 2 then,

`eta = (2(3 + 2 xx 2))/(50 - 3(2) - (2)^2) = (2xx7)/(50 -6 - 4)`

 = `14/40 = 7/20`

Since, < η < 1, the demand is inelastic.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1.4: Applications of Derivatives - Q.4

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 4 Applications of Derivatives
Exercise 4.4 | Q 10.2 | पृष्ठ ११३

संबंधित प्रश्न

Find the marginal revenue if the average revenue is 45 and elasticity of demand is 5.


A manufacturing company produces x items at the total cost of Rs (180 + 4x). The demand function of this product is P = (240 − x). Find x for which profit is increasing.


The total cost function for production of x articles is given as C = 100 + 600x – 3x2 . Find the values of x for which total cost is decreasing.


The manufacturing company produces x items at the total cost of ₹ 180 + 4x. The demand function for this product is P = (240 – x). Find x for which revenue is increasing


The total cost of manufacturing x articles C = 47x + 300x2 – x4 . Find x, for which average cost is decreasing


If the demand function is D = `((p + 6)/(p − 3))`, find the elasticity of demand at p = 4.


If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 5 comment on the result.


For the demand function D = 100 – `p^2/2`. Find the elasticity of demand at p = 10 and comment on the results.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which revenue is increasing.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which profit is increasing.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which also find an elasticity of demand for price 80.


Find MPC, MPS, APC and APS, if the expenditure Ec of a person with income I is given as Ec = (0.0003) I2 + (0.075) I ; When I = 1000.


Fill in the blank:

A road of 108 m length is bent to form a rectangle. If the area of the rectangle is maximum, then its dimensions are _______.


If the marginal revenue is 28 and elasticity of demand is 3, then the price is ______.


If the elasticity of demand η = 1, then demand is ______.


If 0 < η < 1, then the demand is ______.


If the average revenue is 45 and elasticity of demand is 5, then marginal revenue is ______.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price per item is given as p = 120 – x. Find the value of x for which profit is increasing

Solution: Total cost C = 40 + 2x and Price p = 120 − x

Profit π = R – C

∴ π = `square`

Differentiating w.r.t. x,

`("d"pi)/("d"x)` = `square`

Since Profit is increasing,

`("d"pi)/("d"x)` > 0

∴ Profit is increasing for `square`


Complete the following activity to find MPC, MPS, APC and APS, if the expenditure Ec of a person with income I is given as:

Ec = (0.0003)I2 + (0.075)I2

when I = 1000


In a factory, for production of Q articles, standing charges are ₹500, labour charges are ₹700 and processing charges are 50Q. The price of an article is 1700 - 3Q. Complete the following activity to find the values of Q for which the profit is increasing.

Solution: Let C be the cost of production of Q articles.

Then C = standing charges + labour charges + processing charges

∴ C = `square` 

Revenue R = P·Q = (1700 - 3Q)Q = 1700Q- 3Q2

Profit `pi = R - C = square`

 Differentiating w.r.t. Q, we get

`(dpi)/(dQ) = square`

If profit is increasing , then `(dpi)/(dQ) >0`

∴ `Q < square` 

Hence, profit is increasing for `Q < square` 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×