हिंदी

The thermal capacity of a solid is \\frac{400 \mathrm{~J}}{\mathrm{~K}}\. The amount of heat supplied to it will be ______ if its temperature rises by 40 K.

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प्रश्न

The thermal capacity of a solid is \[\frac{400 \mathrm{~J}}{\mathrm{~K}}\]. The amount of heat supplied to it will be ______ if its temperature rises by 40 K.

विकल्प

  • 16000 J

  • 1600 J

  • 1000 J

  • none of these

MCQ
रिक्त स्थान भरें
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उत्तर

The thermal capacity of a solid is \[\frac{400 \mathrm{~J}}{\mathrm{~K}}\]. The amount of heat supplied to it will be 16000 J if its temperature rises by 40 K.

Explanation:

Heat supplied = Thermal capacity × Rise in temperature

$$Q = C'\Delta T$$

= 400 × 40

= 16000 J

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अध्याय 10: Calorimetry - EXERCISE-1 [पृष्ठ २३५]

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 10
अध्याय 10 Calorimetry
EXERCISE-1 | Q 17. | पृष्ठ २३५
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