Advertisements
Advertisements
प्रश्न
The table, given below, shows the values of x and y, where x is proportional (directly proportional) to y.
| x | A | 24 | 15 |
| y | 12 | B | 20 |
The values of A and B are:
विकल्प
A = 16 and B = 18
A = 32 and B = 9
A = 9 and B = 32
A = 18 and B = 16
Advertisements
उत्तर
A = 9 and B = 32
Explanation:
Here x1 = A; x2 = 24; x3 = 15
y1 = 12; y2 = B; y3 = 20
Since x and y are directly proportional to each other.
∴ `x_1/y_1 = x_2/y_2 = x_3/y_3`
`\implies A/12 = 24/B = 15/20`
`\implies A = 15/20 xx 12`
= `3/4 xx 12`
= 9
And `B = (24 xx 20)/15`
= `(24 xx 4)/3`
= 32
संबंधित प्रश्न
Check whether the following numbers are in continued proportion.
1, 2, 3
If `1/12` , x and `1/75` are in continued proportion , find x.
If `a = (b + c)/(2), c = (a + b)/(2)` and b is mean proportional between a and c, prove that `(1)/a + (1)/c = (1)/b`.
Find the fourth proportional to 9.6 kg, 7.2 kg, 28.8 kg
If 9, x, x 49 are in proportion, find the value of x.
If 4 : 5 : : x : 35, then the value of x is
10 books is to 15 books as 3 books is to 15 books
Find the missing number in the box in the proportion:
`16/36 = square/63 = 36/square = square/117`
Unequal masses will not balance on a fulcrum if they are at equal distance from it; one side will go up and the other side will go down.
Unequal masses will balance when the following proportion is true:
`("mass"1)/("length"2) = ("mass"2)/("length"1)`

Two children can be balanced on a seesaw when
`("mass"1)/("length"2) = ("mass"2)/("length"1)`. The child on the left and child on the right are balanced. What is the mass of the child on the right?

The mean proportion between `3 + 2sqrt(2)` and `3 - 2sqrt(2)` is ______.
