Advertisements
Advertisements
प्रश्न
The sum of two angles of a triangle is equal to its third angle. Determine the measure of the third angle.
Advertisements
उत्तर
In the given problem, the sum of two angles of a triangle is equal to its third angle.
We need to find the measure of the third angle.

Thus, it is given, in ΔABC
A+B+C ........(1)
Now, according to the angle sum property of the triangle, we get,
∠A +∠B + ∠C = 180°
∠C + ∠C = 180° (Using 1)
2∠C = 180°
`∠C = (180°)/2`
∠C = 90°
Therefore, the measure of the third angle is
∠C = 90°.
APPEARS IN
संबंधित प्रश्न
Can a triangle have two obtuse angles? Justify your answer in case.
Can a triangle have All angles more than 60°? Justify your answer in case.
State exterior angle theorem.
If the side BC of ΔABC is produced on both sides, then write the difference between the sum of the exterior angles so formed and ∠A.
In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.

An exterior angle of a triangle is equal to 100° and two interior opposite angles are equal. Each of these angles is equal to
In the given figure, show that: ∠a = ∠b + ∠c

(i) If ∠b = 60° and ∠c = 50° ; find ∠a.
(ii) If ∠a = 100° and ∠b = 55° : find ∠c.
(iii) If ∠a = 108° and ∠c = 48° ; find ∠b.
One of the base angles of an isosceles triangle is 52°. Find its angle of the vertex.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
15 cm, 20 cm, 25 cm
What is the sum of the measures of the interior angles of any triangle, △ABC?
