हिंदी

The sum of squares of first n natural numbers is given by 16n(n+1)(2n+1) or 16(2n3+3n2+n). Find the sum of squares of the first 10 natural numbers.

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प्रश्न

The sum of squares of first n natural numbers is given by `1/6n(n + 1)(2n + 1)` or `1/6(2n^3 + 3n^2 + n)`. Find the sum of squares of the first 10 natural numbers.

योग
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उत्तर

Given, the sum of squares of first n natural numbers = `1/6(n +1)(2n + 1)`

∴ The sum of squares of first 10 natural numbers  ...[∴ Put n = 10]

= `1/6 (10)(10 + 1)(2 xx 10+1)`

= `1/6 xx 10 xx 11 xx 21`

= 385

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अध्याय 10: Algebraic Expressions - Exercise [पृष्ठ ३२७]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar Class 7
अध्याय 10 Algebraic Expressions
Exercise | Q 87. | पृष्ठ ३२७

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