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प्रश्न
The sum of 10 values is 100 and the sum of their squares is 1090. Find out the coefficient of variation.
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उत्तर
∑X = 100
N = 10
So, `overlineX = (sumX)/N = 100/10 = 10`
`sumX^2 = 1090`
`sigma = sqrt((sumX^2)/N - (overlineX)^2)`
= `sqrt(1090/10 - (10)^2)`
= `sqrt9`
= 3
CV = `sigma/overlineX xx 100`
= `3/10 xx 100 = 30`
संबंधित प्रश्न
In a town, 25% of the persons earned more than Rs 45,000 whereas 75% earned more than 18,000. Calculate the absolute and relative values of dispersion.
The yield of wheat and rice per acre for 10 districts of a state is as under:
|
District |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
| Wheat |
12 |
10 |
15 |
19 |
21 |
16 |
18 |
9 |
25 |
10 |
| Rice |
22 |
29 |
12 |
23 |
18 |
15 |
12 |
34 |
18 |
12 |
Calculate for each crop,
Which crop has greater variation?
In the previous question, calculate the relative measures of variation and indicate the value which, in your opinion, is more reliable.
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| X |
25 |
85 |
40 |
80 |
120 |
| Y |
50 |
70 |
65 |
45 |
80 |
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- a higher run-getter, or
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|
Life (in hrs) |
No. of bulbs | |
| Brand A | Brand B | |
|
0 - 50 |
15 |
2 |
|
50 - 100 |
20 |
8 |
|
100 - 150 |
18 |
60 |
|
150 - 200 |
25 |
25 |
|
200 - 250 |
22 |
5 |
|
100 |
100 |
|
Which brand gives higher life?
To check the quality of two brands of lightbulbs, their life in burning hours was estimated as under for 100 bulbs of each brand.
|
Life (in hrs) |
No. of bulbs | |
| Brand A | Brand B | |
|
0 - 50 |
15 |
2 |
|
50 - 100 |
20 |
8 |
|
100 - 150 |
18 |
60 |
|
150 - 200 |
25 |
25 |
|
200 - 250 |
22 |
5 |
|
100 |
100 |
|
Which brand is more dependable?
