Advertisements
Advertisements
प्रश्न
The sum of the first three terms of an Arithmetic Progression (A.P.) is 42 and the product of the first and third term is 52. Find the first term and the common difference.
Advertisements
उत्तर
Let the three times terms of an A.P. be (a - d ),a, (a + d)
sum = 42 = (a - d) + a + (a + d)
42 = 3a
⇒ ` a = 42/3`
⇒ a = 14
Also , (a - d ) (a + d) = 52
⇒ ` a^2 - d^2 = 52 `
`d^2 = a^2 - 52`
` = 196 - 52 `
`d^2 = 144`
⇒ `d = +- 12`
∴ First term ` = {(a - d,=,14,+,12,=,26),(a + d,=,14,-,12,=,2):}`
∴ A.P. is 2, 14, 26 or 26,14,2
APPEARS IN
संबंधित प्रश्न
The first term of an A.P. is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.
In an A.P., if the first term is 22, the common difference is −4 and the sum to n terms is 64, find n.
Find the sum of the first 13 terms of the A.P: -6, 0, 6, 12,....
Find the sum 2 + 4 + 6 ... + 200
How many two-digits numbers are divisible by 3?
Write an A.P. whose first term is a and common difference is d in the following.
a = –19, d = –4
Write the value of x for which 2x, x + 10 and 3x + 2 are in A.P.
Q.14
Obtain the sum of the first 56 terms of an A.P. whose 18th and 39th terms are 52 and 148 respectively.
In an AP, if Sn = n(4n + 1), find the AP.
