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The Sum of First Three Terms of an Ap is 48. If the Product of First and Second Terms Exceeds 4 Times the Third Term by 12. Find the Ap. - Mathematics

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प्रश्न

The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.

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उत्तर

Let the first three terms of the AP be (a-d) , a and (a+d) . then 

(a-d) + a+(a+d) = 48

⇒ 3a = 48 

⇒ a= 16 

Now, 

(a-d)× a = 4 (a+d)  + 12      (Given) 

⇒ (16-d) × 16 = 4(16 +d) +12

⇒ 256-16d = 64 +4d +12

⇒16d + 4d=256-76

⇒ 20d=180

⇒ d=9

When a = 16 and d = 9  ,

a-d = 16-9=7

a+d = 16+9=25

Hence, the first three terms of the AP are 7, 16, and 25.

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अध्याय 11: Arithmetic Progression - Exercises 2

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 11 Arithmetic Progression
Exercises 2 | Q 13

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