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If first term of an A.P. is a, second term is b and last term is c, then show that sum of all terms is (a+c)(b+c−2a)2(b−a). - Algebra Mathematics 1

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प्रश्न

If first term of an A.P. is a, second term is b and last term is c, then show that sum of all terms is  \[\frac{\left( a + c \right) \left( b + c - 2a \right)}{2\left( b - a \right)}\].

योग
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उत्तर

a, b, ..., c

t1 = a, d = b - a, tn = c

We know that

tn = a + (n - 1)d

c = a + (n - 1)(b - a)

`(c-a)/(b-a)=n-1` 

`(c-a)/(b-a)+1/1=n`

`(c-a+b-a)/(b-a)=n`

∴ n = `(c+b-2a)/(b-a)`      ...(1)

Now, 

Sn = `n/2[t_1 + t_n]`

Sn = `(c+b-2a)/((b-a)2)[a+c]`

Sn = `((a+c)(b+c-2a))/(2(b-a))`

Hence proved.

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अध्याय 3: Arithmetic Progression - Problem Set 3 [पृष्ठ ८०]

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बालभारती Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
अध्याय 3 Arithmetic Progression
Problem Set 3 | Q 11 | पृष्ठ ८०

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