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प्रश्न
The specific heat capacity of water is 1 cal/g °C.
विकल्प
Right
Wrong
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उत्तर
The specific heat capacity of water is 1 cal/g °C- Right
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संबंधित प्रश्न
Write the approximate value of specific heat capacity of water in S.I. unit.
Write the expression for the heat energy Q received by the substance when m kg of substance of specific heat capacity c Jkg-1 k-1 is heated through Δt° C.
Give one example where high specific heat capacity of water is used as heat reservoir ?
The S.I. unit of specific heat capacity is ______.
45 g of water at 50°C in a beaker is cooled when 50 g of copper at 18° C is added to it. The contents are stirred till a final constant temperature is reached. Calculate this final temperature. The specific heat capacity of copper is 0.39 J g-1K-1 and that of water is 4.2 J g-1K-1. State the assumption used.
How will rise in sea level affect population in coastal countries?
State, with reason, which of the two, boiling water or steam both at 100°C will produce more severe burns.
Fill in the following blank using suitable word:
SI unit of heat is .........
A liquid X has specific heat capacity higher than the liquid Y. Which liquid is useful as coolant in car radiators.
A piece of iron of mass 2.0 kg has a heat capacity of 966 J K-1. Find its specific heat capacity in S.I unit.
Why is specific heat capacity taken as a measure of thermal inertia?
Will the value of specific heat’capacity and specific latent heat of a substance change if the scale is °F instead of °C?
The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate Specific heat capacity of lead.
Derive an expression for finding out the specific heat capacity of a body (solid) from the readings of an experiment given below:
(i) Mass of empty calorimeter (with stirrer) = m1 gm
(ii) Mass of the metal piece = M gm
(iii) Mass of colorimeter and water = m2 gm
(iv) Initial temperature and water = t1°C
(v) Temperature of hot solid (metal piece) = t2 °C
(vi) Final temperature of the mixture = t°C
(vii) Specific heat of calorimeter = 0.4 J gm / °C
How much heat energy is necessary to raise the temperature of 5 kg of water from 20°C to 100°C?
Read the passage and answer the questions based on it.
If heat is exchanged between a hot and cold object, the temperature of the cold object goes on increasing due to gain of energy and the temperature of the hot object goes on decreasing due to loss of energy. The change in temperature continues till the temperatures of both objects attain the same value. In this process, the cold object gains heat energy and the hot object loses heat energy. If the system of both the objects is isolated from the environment by keeping it inside a heat-resistant box then no energy can flow from inside the box or come into the box. In this situation, we get the following principle.
Heat energy lost by the hot object = Heat energy gained by the cold object. This is called the ‘Principle of heat exchange’.
- Where does heat transfer take place?
- In such a situation which principle of heat do you perceive?
- How can this principle be explained in short?
- Which property of the substance is measured using this principle?
Define specific heat capacity.
Numerical Problem.
How much heat energy is required to change 2 kg of ice at 0°C into water at 20°C? (Specific latent heat of fusion of water = 3,34,000 J/kg, Specific heat capacity of water = 4200 JKg–1K–1).
Which of the following substances (A, B and C) has the highest specific heat?
