हिंदी

The sides of a right-angled triangle are (x – 1) cm, 3x cm and (3x + 1) cm. Find: the value of x, the lengths of its sides, its area.

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प्रश्न

The sides of a right-angled triangle are (x – 1) cm, 3x cm and (3x + 1) cm. Find:

  1. the value of x,
  2. the lengths of its sides,
  3. its area.
योग
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उत्तर

Longer side = Hypotenuse = (3x + 1) cm

Lengths of other two sides are (x – 1) cm and 3x cm.

Using Pythagoras theorem,

(3x + 1)2 = (x – 1)2 + (3x)2

9x2 + 1 + 6x = x2 + 1 – 2x + 9x2

x2 – 8x = 0

x(x – 8) = 0

x = 0, 8

But, if x = 0, then one side = 3x = 0, which is not possible.

So, x = 8

Thus, the lengths of the sides of the triangle are (x – 1) cm = 7 cm, 3x cm = 24 cm and (3x + 1) cm = 25 cm.

Area of the triangle = `1/2` × 7 cm × 24 cm = 84 cm2

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अध्याय 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (B) [पृष्ठ ७१]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (B) | Q 3. | पृष्ठ ७१

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