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प्रश्न
The regression coefficient of Y on X
विकल्प
bxy = `("N"sum"dxdy" - (sum"dx")(sum"dy"))/("N"sum"dy"^2 - (sum"dy")^2)`
byx = `("N"sum"dxdy" - (sum"dx")(sum"dy"))/("N"sum"dy"^2 - (sum"dy")^2)`
byx = `("N"sum"dxdy" - (sum"dx")(sum"dy"))/("N"sum"dx"^2 - (sum"dx")^2)`
bxy = `("N"sum"xy" - (sum"x")(sum"y"))/(sqrt("N"sum"x"^2 - (sum"x")^2) xx sqrt("N"sum"y"^2 - (sum"y")^2))`
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उत्तर
byx = `("N"sum"dxdy" - (sum"dx")(sum"dy"))/("N"sum"dx"^2 - (sum"dx")^2)`
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Using the following information you are requested to
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Here X is the expenditure on inspection, Y is the defective parts delivered.
The following information is given.
| Details | X (in ₹) | Y (in ₹) |
| Arithmetic Mean | 6 | 8 |
| Standard Deviation | 5 | `40/3` |
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