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From the data given below: Marks in Economics: 25 28 35 32 31 36 29 38 34 32 Marks in Statistics: 43 46 49 41 36 32 31 30 33 39 Find The two regression equations,

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प्रश्न

From the data given below:

Marks in Economics: 25 28 35 32 31 36 29 38 34 32
Marks in Statistics: 43 46 49 41 36 32 31 30 33 39

Find

  1. The two regression equations,
  2. The coefficient of correlation between marks in Economics and Statistics,
  3. The mostly likely marks in Statistics when the marks in Economics is 30.
योग
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उत्तर

Marks in Economics (X) Marks in Statistics (Y) x = `"X" - bar"X"` y = `"Y" - bar"Y"` x2 y2 xy
25 43 − 7 5 49 25 − 35
28 46 − 4 8 16 64 − 32
35 49 3 11 9 121 33
32 41 0 3 0 9 0
31 36 − 1 − 2 1 4 2
36 32 4 − 6 16 36 − 24
29 31 − 3 − 7 9 49 21
38 30 6 − 8 36 64 − 48
34 33 2 − 5 4 25 − 10
32 39 0 1 0 1 0
320 380 0 0 140 398 − 93

N = 10, ∑X = 320, ∑Y = 280, ∑x2 = 140, ∑y2 = 398, ∑xy = − 93, `bar"X" = 320/100` = 32, `bar"Y" = 380/100` = 38

(a) Regression equation of X on Y.

bxy = `"r"(sigma_"x")/(sigma_"y") = (sum"xy")/(sum"y"^2) = (-93)/398` = − 0.234

`"X" - bar"X" = "b"_"xy"("Y" - bar"Y")`

X − 32 = − 0.234(Y − 38)

X = − 0.234Y + 8.892 + 32

X = − 0.234Y + 40.892

Regression equation of Y on X.

`"Y" - bar"Y" = "b"_"xy"("X" - bar"X")`

byx = `"r"(sigma_"x")/(sigma_"y") = (sum"xy")/(sum"y"^2) = (-93)/140` = − 0.664

Y − 38 = − 0.664(X − 32)

Y = − 0.664X + 21.248 + 38

Y = − 0.664X + 59.248

(b) Coefficient of correlation (r) = `±sqrt("b"_"xy" xx "b"_"yx")`

= `sqrt((-0.234)(-0.664))`

= − 0.394

(c) When X = 30, Y = ?

Y = − 0.664(30) + 59.248

= − 19.92 + 59.248

= 39.328

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Regression Analysis
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Correlation and Regression Analysis - Exercise 9.2 [पृष्ठ २२६]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
अध्याय 9 Correlation and Regression Analysis
Exercise 9.2 | Q 1 | पृष्ठ २२६

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