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The perimeter of an arc of radius 4.2 cm is 12.8 cm. Determine the angle subtended by the arc at the centre of circle. - Geometry Mathematics 2

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प्रश्न

The perimeter of an arc of radius 4.2 cm is 12.8 cm. Determine the angle subtended by the arc at the centre of circle.

योग
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उत्तर


Given: Radius of arc = 4.2 cm and perimeter of arc = 12.8 cm.

Consider the sector OACB,

Length of the arc ABC = `θ/360^circ xx 2 πr`  ......(i)

Perimeter of the sector OACB  = OA + arc ACB + OB

= `r + θ/360 xx 2πr + r`

= `2r + θ/360 xx 2πr`

 Thus, the perimeter of the arc = `2r + θ/360 xx 2πr`

According to the question,

`2r + θ/360 xx 2πr` = 12.8  ......(ii)

Substituting the value of r in equation (ii),

`2 xx 4.2 + θ/360 xx 2π xx 4.2` = 12.8

`8.4 + θ/360 xx 2π xx 4.2` = 12.8

`θ/360 xx 2π xx 4.2` = 12.8 – 8.4

`θ/360 xx 2 xx 22/7 xx 4.2` = 4.4

`θ/360 xx 2 xx 22 xx 0.6` = 4.4

θ = `(4.4 xx 360)/(22 xx 0.6 xx 2)` = 60°

As a result, the circle's center's arc subtends a 60° angle.

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