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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ८

For the sectors with given measures, find the length of the arc, area and perimeter. (π = 3.14) central angle 120°, d = 12.6 cm

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प्रश्न

For the sectors with given measures, find the length of the arc, area and perimeter. (π = 3.14)

central angle 120°, d = 12.6 cm

योग
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उत्तर

∴ r = `12.6/2  "cm"`

r = 6.3 cm

Length of the arc l = `(theta^circ)/(360^circ) xx 2pi"r"  "units"`

l = `(120^circ)/(360^circ) xx  2 xx 3.14 xx 63  "cm"`

l = 13.188 cm

I = 13.19 cm

Area of the sector A = `(theta^circ)/(360^circ) xx pi"r"^2  "units"`

A = `(120^circ)/(360^circ) xx 3.14 xx 6.3 xx 63  "cm"^2`

A = 3.14 × 6.3 × 2.1 cm2

A = 41.54 cm2

Perimeter of the sector P = l + 2r cm

P = 13.19 + 2(6.3) cm

= 13.19 + 12.6 cm

P = 25.79 cm

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अध्याय 2: Measurements - Exercise 2.1 [पृष्ठ ५८]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
अध्याय 2 Measurements
Exercise 2.1 | Q 4. (ii) | पृष्ठ ५८

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