Advertisements
Advertisements
प्रश्न
The perimeter of a rectangular field is 82 m and its area is 400 m2. Find the breadth of the rectangle.
Advertisements
उत्तर
Let the breadth of the rectangle be x meters. Then
Perimeter = 82 meters
2(length + breadth) = 82
(length + x) = 41
length = 41 − x
And area of the rectangle
length x bradth = 400
(41 − x) x = 400
41x − x2 = 400
x2 − 41x + 400 = 0
x2 − 25x − 16x + 400 = 0
x(x − 25) −16(x − 25) = 0
(x − 25) (x − 16) = 0
or
x − 16 = 0
x = 16
Since perimeter is 82 meter. So breadth can’t be 25 meter.
Hence, breadth 16 meters.
संबंधित प्रश्न
Solve the equation:`14/(x+3)-1=5/(x+1); xne-3,-1` , for x
Find the whole numbers which when decreased by 20 is equal to 69 times the reciprocal of the members.
`8x^2-14x-15=0`
Write the set of value of k for which the quadratic equations has 2x2 + kx − 8 = 0 has real roots.
Solve the following equation: 4x2 + 16x = 0
Write the number of zeroes in the end of a number whose prime factorization is 22 × 53 × 32 × 17.
Solve the following equation by factorization
`(x + 1)/(x - 1) + (x - 2)/(x + 2)` = 3
Rs. 7500 is divided equally among a certain number of children. Had there been 20 less children, each would have receive Rs 100 more. Find the original number of children.
A man spent Rs. 2800 on buying a number of plants priced at Rs x each. Because of the number involved, the supplier reduced the price of each plant by Rupee 1.The man finally paid Rs. 2730 and received 10 more plants. Find x.
For equation `1/x + 1/(x - 5) = 3/10`; one value of x is ______.
