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प्रश्न
The perimeter of a rectangle is 28x3+ 16x2 + 8x + 4. One of its sides is 8x2 + 4x. Find the other side
योग
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उत्तर
Perimeter of a rectangle (2l + 2b)
= 28x3 + 16x2 + 8x + 4
Let one side (l) = 8x2 + 4x
∴ 2l = 2 (8x2 + 4x) = 16x2 + 8x
∴ 2b = (28x3 + 16x2 + 8x + 4) - (16x2 + 8x)
= 28x3 + 16x2 + 8x + 4 - 16x2 - 8x
= 28x3 + 4
∴ Other side (b) = `(28"x"^3 + 4)/2 = 14"x"^3 + 2`
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