Advertisements
Advertisements
प्रश्न
By how much is 3x3 – 2x2y + xy2 -y3 less than 4x3 – 3x2y – 7xy2 +2y3
Advertisements
उत्तर
We can get the required results by substracting
3x3 – 2x2y + xy2 -y3 from 4x3 – 3x2y – 7xy2 +2y3
= (4x3 – 3x2y – 7xy2 +2y3 ) - (3x3 – 2x2y + xy2 -y3)
= 4x3 – 3x2y – 7xy2 +2y3 - 3x3 + 2x2y - xy2 + y3
= 4x3 - 3x3 – 3x2y + 2x2y – 7xy2 - xy2 +2y3 + y3
= x3 - x2y - 8xy2 + 3y3
APPEARS IN
संबंधित प्रश्न
Subtract: 4p + p2 from 3p2 - 8p
The perimeter of a triangle is 14a2 + 20a + 13. Two of its sides are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
If m = 9x2 - 4xy + 5y2 and n = - 3x2 + 2xy - y2 find: 2m - n
Simplify: 5(x − 4) − 3(x − 4) + 7(x − 4)
Copy and complete the following multi-plication:
2a - b + 3c
× 2a - 4b
Multiply: mn4, m3n and 5m2n3
Simplify: `"x" + "x"/2 + "x"/3`
Simplify: `"y"/5 + "y" - "19y"/15`
Simplify: `"2a + 1"/3 + "3a - 1"/2`
Simplify: `"k + 1"/2 + "2k - 1"/3 - "k + 3"/4`
