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प्रश्न
The perimeter of a quadrant is 50 cm. Find its diameter. `["Take" π = 22/7]`
योग
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उत्तर
Given:
- The perimeter of a quadrant is 50 cm.
- Use [Take `π = 22/7`].
Step-wise calculation:
1. The perimeter (P) of a quadrant is given by the sum of the two radii and the quarter circumference:
`P = 2r + 1/4 xx 2πr`
`P = 2r + (πr)/2`
2. Substitute `π = 22/7`:
`P = 2r + 22/7 xx r/2`
`P = 2r + (11r)/7`
`P = (14r + 11r)/7`
`P = (25r)/7`
3. Given perimeter P = 50 cm,
Solve for (r):
`(25r)/7 = 50`
⇒ `25r xx 50 xx 7 = 350`
⇒ `r = 350/25`
⇒ r = 14 cm
4. The diameter d = 2r
= 2 × 14
= 28 cm
The diameter of the quadrant is 28 cm.
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