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The monthly maximum temperature of a city is given in degree celcius in the following data. answer the following questions. 1. For how many days the maximum temperature was less than 34oC? - Algebra

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प्रश्न

The monthly maximum temperature of a city is given in degree celcius in the following data. By taking suitable classes, prepare the grouped frequency distribution table

29.2, 29.0, 28.1, 28.5, 32.9, 29.2, 34.2, 36.8, 32.0, 31.0, 30.5, 30.0, 33, 32.5, 35.5, 34.0, 32.9, 31.5, 30.3, 31.4, 30.3, 34.7, 35.0, 32.5, 33.5, 29.0, 29.5, 29.9, 33.2, 30.2

From the table, answer the following questions.

  1. For how many days the maximum temperature was less than 34oC?
  2. For how many days the maximum temperature was 34oC or more than 34oC?
योग
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उत्तर

The monthly maximum temperature of a city is given in degree celcius in the following data:

29.2, 29.0, 28.1, 28.5, 32.9, 29.2, 34.2, 36.8, 32.0, 31.0, 30.5, 30.0, 33, 32.5, 35.5, 34.0, 32.9, 31.5, 30.3, 31.4, 30.3, 34.7, 35.0, 32.5, 33.5, 29.0, 29.5, 29.9, 33.2, 30.2

The grouped frequency distribution table of the given data is as follows:

Class (Temperature) Tally marks Frequency
28 - 30  `cancel(bb|bb|bb|bb|)` `bb|bb|bb|` 8
30 - 32  `cancel(bb|bb|bb|bb|)` `bb|bb|bb|` 8
32 - 34  `cancel(bb|bb|bb|bb|)` `bb|bb|bb|` 8
34 - 36  `cancel(bb|bb|bb|bb|)` 5
36 - 38 `bb|` 1
    Total N = 30
  1. The number of days the maximum temperature was less than 34oC = 8 + 8 + 8 = 24.
  2. The number of days the maximum temperature was 34oC or more than 34oC = 5 + 1 = 6.
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अध्याय 7: Statistics - Problem Set 7 [पृष्ठ १२७]

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बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
अध्याय 7 Statistics
Problem Set 7 | Q (4) | पृष्ठ १२७

संबंधित प्रश्न

Find the class-mark of the class 35-40.


Complete the Following Table.

Classes (age) Tally marks Frequency
(No. of students)
12-13 `cancel(bb|bb|bb|bb|)` `square`
13-14 `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` `bb|bb|bb|bb|` `square`
14-15 `square` `square`
15-16 `bb|bb|bb|bb|` `square`
    N = ∑f = 35

In a ‘tree plantation’ project of a certain school there are 45 students of 'Harit Sena'. The record of trees planted by each student is given below:

3, 5, 7, 6, 4, 3, 5, 4, 3, 5, 4, 7, 5, 3, 6, 6, 5, 3, 4, 5, 7, 3, 5, 6, 4, 4, 3, 5, 6, 6, 4, 3, 5, 7, 3, 4, 5, 7, 6, 4, 3, 5, 4, 4, 7.

Prepare a frequency distribution table of the data.


In a school, 46 students of 9th standard, were told to measure the lengths of the pencils in their compass boxes in centimeters. The data collected was as follows.

16, 15, 7, 4.5, 8.5, 5.5, 5, 6.5, 6, 10, 12, 13, 4.5, 4.9, 16, 11, 9.2, 7.3, 11.4, 12.7, 13.9, 16, 5.5, 9.9, 8.4, 11.4, 13.1, 15, 4.8, 10, 7.5, 8.5, 6.5, 7.2, 4.5, 5.7, 16, 5.7, 6.9, 8.9, 9.2, 10.2, 12.3, 13.7, 14.5, 10.

By taking inclusive classes 0-5, 5-10, 10-15.... prepare a grouped frequency distribution table.


In a village, the milk was collected from 50 milkmen at a collection center in litres as given below:

27, 75, 5, 99, 70, 12, 15, 20, 30, 35, 45, 80, 77, 90, 92, 72, 4, 33, 22, 15, 20, 28, 29, 14, 16, 20, 72, 81, 85, 10, 16, 9, 25, 23, 26, 46, 55, 56, 66, 67, 51, 57, 44, 43, 6, 65, 42, 36, 7, 35.

By taking suitable classes, prepare grouped frequency distribution table.


What is the class-mark of class 25-35?


Given below are the marks obtained by 30 students in an examination:

08 17 33 41 47 23 20 34
09 18 42 14 30 19 29 11
36 48 40 24 22 02 16 21
15 32 47 44 33 01    

Taking class intervals 1-10, 11-20, ....., 41-50; make a frequency table for the above distribution.


Construct a frequency table from the following data:

Marks No. of students
less than 10 6
less than 20 15
less than 30 30
less than 40 39
less than 50 53
less than 60 70

Construct a cumulative frequency distribution table from the frequency table given below:
( i )

Class Interval Frequency
0 - 8  9
8 - 16  13
16 - 24  12
24 - 32  7
32 - 40  15

( ii )

Class Interval  Frequency 
1 - 10  12
11 - 20 18
21 - 30 23
31 - 40 15
41 - 50 10

Construct a cumulative frequency distribution table from the frequency table given below:

Class Interval Frequency
1 - 10 12
11 - 20 18
21 - 30 23
31 - 40 15
41 - 50 10

The range of the data 200, 15, 20, 103, 3, 196, is _____________


Form a continuous frequency distribution table for the marks obtained by 30 students in a X std public examination.

328, 470, 405, 375, 298, 326, 276, 362, 410, 255, 391, 370, 455, 229, 300, 183, 283, 366, 400, 495, 215, 157, 374, 306, 280, 409, 321, 269, 398, 200


In a class interval the upper limit of one class is the lower limit of the other class. This is _________ series


The difference between the upper and lower limit of a class interval is called the ______ of the class interval.


Using the following frequency table.

Marks (obtained out of 10) 4 5 7 8 9 10
Frequency 5 10 8 6 12 9

9 students got full marks.


Given below is a frequency distribution table. Read it and answer the questions that follow:

Class Interval Frequency
10 – 20 5
20 – 30 10
30 – 40 4
40 – 50 15
50 – 60 12
  1. What is the lower limit of the second class interval?
  2. What is the upper limit of the last class interval?
  3. What is the frequency of the third class?
  4. Which interval has a frequency of 10?
  5. Which interval has the lowest frequency?
  6. What is the class size?

The marks obtained (out of 20) by 30 students of a class in a test are as follows:

14, 16, 15, 11, 15, 14, 13, 16, 8, 10, 7, 11, 18, 15, 14, 19, 20, 7, 10, 13, 12, 14, 15, 13, 16, 17, 14, 11, 10, 20.

Prepare a frequency distribution table for the above data using class intervals of equal width in which one class interval is 4 – 8 (excluding 8 and including 4).


The weights (in kg) of 30 students of a class are:

39, 38, 36, 38, 40, 42, 43, 44, 33, 33, 31, 45, 46, 38, 37, 31, 30, 39, 41, 41, 46, 36, 35, 34, 39, 43, 32, 37, 29, 26.

Prepare a frequency distribution table using one class interval as (30 – 35), 35 not included.

  1. Which class has the least frequency?
  2. Which class has the maximum frequency?

Complete the following table:

Weights
(in kg.)
Tally Marks Frequency
(Number of persons)
40 – 50 `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|`  
50 – 60 `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|bb|bb|`  
60 – 70 `\cancel(bb|bb|bb|bb|) bb|`  
70 – 80 `bb|bb|`  
80 – 90 `bb|`  

Find the total number of persons whose weights are given in the above table.


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